b^2/7b+7

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Solution for b^2/7b+7 equation: 


b in (-oo:+oo)

b*((b^2)/7)+7 = 0

1/7*b^3 = -7 // : 1/7

b^3 = -49

b^3 = -49 // ^ 1/3

b = -49^(1/3)

b = -49^(1/3)

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